Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …0001110010001000011110 |
3 | 1201110202222112120002220012 |
4 | 2332333333201302020132 |
5 | 3210021321001313304 |
6 | 43525421525523222 |
7 | 2523164643225353 |
oct | 276777741621036 |
9 | 51422875502805 |
10 | 13125412135454 |
11 | 4200501a76333 |
12 | 157b961b73512 |
13 | 74294b2014a8 |
14 | 3353b807262a |
15 | 17b64e85316e |
hex | befff87221e |
13125412135454 has 4 divisors (see below), whose sum is σ = 19688118203184. Its totient is φ = 6562706067726.
The previous prime is 13125412135391. The next prime is 13125412135463. The reversal of 13125412135454 is 45453121452131.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×131254121354542 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281353033862 + ... + 3281353033865.
It is an arithmetic number, because the mean of its divisors is an integer number (4922029550796).
Almost surely, 213125412135454 is an apocalyptic number.
13125412135454 is a deficient number, since it is larger than the sum of its proper divisors (6562706067730).
13125412135454 is an equidigital number, since it uses as much as digits as its factorization.
13125412135454 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6562706067729.
The product of its digits is 288000, while the sum is 41.
Adding to 13125412135454 its reverse (45453121452131), we get a palindrome (58578533587585).
The spelling of 13125412135454 in words is "thirteen trillion, one hundred twenty-five billion, four hundred twelve million, one hundred thirty-five thousand, four hundred fifty-four".
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