Base | Representation |
---|---|
bin | 1011111011111111111110… |
… | …1110101010001111100011 |
3 | 1201110202222202220121021211 |
4 | 2332333333232222033203 |
5 | 3210021322332323021 |
6 | 43525422130130551 |
7 | 2523165014014546 |
oct | 276777756521743 |
9 | 51422882817254 |
10 | 13125415511011 |
11 | 4200503971451 |
12 | 157b963120a57 |
13 | 74294bb13a6b |
14 | 3353b86b085d |
15 | 17b64ecbd3e1 |
hex | befffbaa3e3 |
13125415511011 has 2 divisors, whose sum is σ = 13125415511012. Its totient is φ = 13125415511010.
The previous prime is 13125415510957. The next prime is 13125415511059. The reversal of 13125415511011 is 11011551452131.
It is a strong prime.
It is an emirp because it is prime and its reverse (11011551452131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13125415511011 - 29 = 13125415510499 is a prime.
It is not a weakly prime, because it can be changed into another prime (13125415511111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562707755505 + 6562707755506.
It is an arithmetic number, because the mean of its divisors is an integer number (6562707755506).
Almost surely, 213125415511011 is an apocalyptic number.
13125415511011 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125415511011 is an equidigital number, since it uses as much as digits as its factorization.
13125415511011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3000, while the sum is 31.
Adding to 13125415511011 its reverse (11011551452131), we get a palindrome (24136966963142).
The spelling of 13125415511011 in words is "thirteen trillion, one hundred twenty-five billion, four hundred fifteen million, five hundred eleven thousand, eleven".
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