Base | Representation |
---|---|
bin | 1011111100000000000001… |
… | …0011110000000001001111 |
3 | 1201110210000110012120201111 |
4 | 2333000000103300001033 |
5 | 3210021332324441444 |
6 | 43525423114352451 |
7 | 2523165162451501 |
oct | 277000023600117 |
9 | 51423013176644 |
10 | 13125425233999 |
11 | 4200509402481 |
12 | 157b96642b727 |
13 | 742950b39500 |
14 | 3353b9ac1d71 |
15 | 17b650a8e234 |
hex | bf0004f004f |
13125425233999 has 12 divisors (see below), whose sum is σ = 14960777442600. Its totient is φ = 11478104655264.
The previous prime is 13125425233967. The next prime is 13125425234059. The reversal of 13125425233999 is 99933252452131.
It is not a de Polignac number, because 13125425233999 - 25 = 13125425233967 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13125425233699) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2043818844 + ... + 2043825265.
It is an arithmetic number, because the mean of its divisors is an integer number (1246731453550).
Almost surely, 213125425233999 is an apocalyptic number.
13125425233999 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
13125425233999 is a deficient number, since it is larger than the sum of its proper divisors (1835352208601).
13125425233999 is a wasteful number, since it uses less digits than its factorization.
13125425233999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4087644154 (or 4087644141 counting only the distinct ones).
The product of its digits is 15746400, while the sum is 58.
The spelling of 13125425233999 in words is "thirteen trillion, one hundred twenty-five billion, four hundred twenty-five million, two hundred thirty-three thousand, nine hundred ninety-nine".
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