Base | Representation |
---|---|
bin | 1011111100000000000001… |
… | …0011110000000000101111 |
3 | 1201110210000110012120200022 |
4 | 2333000000103300000233 |
5 | 3210021332324441332 |
6 | 43525423114352355 |
7 | 2523165162451424 |
oct | 277000023600057 |
9 | 51423013176608 |
10 | 13125425233967 |
11 | 4200509402452 |
12 | 157b96642b6bb |
13 | 742950b394a7 |
14 | 3353b9ac1d4b |
15 | 17b650a8e212 |
hex | bf0004f002f |
13125425233967 has 2 divisors, whose sum is σ = 13125425233968. Its totient is φ = 13125425233966.
The previous prime is 13125425233933. The next prime is 13125425234059. The reversal of 13125425233967 is 76933252452131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13125425233967 - 210 = 13125425232943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13125425239967) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562712616983 + 6562712616984.
It is an arithmetic number, because the mean of its divisors is an integer number (6562712616984).
Almost surely, 213125425233967 is an apocalyptic number.
13125425233967 is a deficient number, since it is larger than the sum of its proper divisors (1).
13125425233967 is an equidigital number, since it uses as much as digits as its factorization.
13125425233967 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8164800, while the sum is 53.
The spelling of 13125425233967 in words is "thirteen trillion, one hundred twenty-five billion, four hundred twenty-five million, two hundred thirty-three thousand, nine hundred sixty-seven".
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