Base | Representation |
---|---|
bin | 1011111100000000000100… |
… | …1100101000011011101111 |
3 | 1201110210001111021010221210 |
4 | 2333000001030220123233 |
5 | 3210021400134121020 |
6 | 43525424410125503 |
7 | 2523165433264263 |
oct | 277000114503357 |
9 | 51423044233853 |
10 | 13125440145135 |
11 | 420051686742a |
12 | 157b96b420893 |
13 | 742953c5a576 |
14 | 3353bba840a3 |
15 | 17b6520373e0 |
hex | bf0013286ef |
13125440145135 has 32 divisors (see below), whose sum is σ = 21729394975680. Its totient is φ = 6757438464000.
The previous prime is 13125440145043. The next prime is 13125440145143. The reversal of 13125440145135 is 53154104452131.
It is not a de Polignac number, because 13125440145135 - 210 = 13125440144111 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13125440145093 and 13125440145102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1053976 + ... + 5230845.
It is an arithmetic number, because the mean of its divisors is an integer number (679043592990).
Almost surely, 213125440145135 is an apocalyptic number.
13125440145135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13125440145135 is a deficient number, since it is larger than the sum of its proper divisors (8603954830545).
13125440145135 is a wasteful number, since it uses less digits than its factorization.
13125440145135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6289659.
The product of its (nonzero) digits is 144000, while the sum is 39.
Adding to 13125440145135 its reverse (53154104452131), we get a palindrome (66279544597266).
The spelling of 13125440145135 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty million, one hundred forty-five thousand, one hundred thirty-five".
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