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13125442512502 = 211940195496329
BaseRepresentation
bin1011111100000000000101…
…0101101010011001110110
31201110210001122201102101001
42333000001111222121312
53210021401240400002
643525424532553514
72523165462354235
oct277000125523166
951423048642331
1013125442512502
114200518134031
12157b97018289a
137429545a8c88
143353bc0dcb1c
1517b652353a87
hexbf00156a676

13125442512502 has 8 divisors (see below), whose sum is σ = 19688183839800. Its totient is φ = 6562714565904.

The previous prime is 13125442512473. The next prime is 13125442512503. The reversal of 13125442512502 is 20521524452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×131254425125022 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125442512503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 360127 + ... + 5136202.

It is an arithmetic number, because the mean of its divisors is an integer number (2461022979975).

Almost surely, 213125442512502 is an apocalyptic number.

13125442512502 is a deficient number, since it is larger than the sum of its proper divisors (6562741327298).

13125442512502 is a wasteful number, since it uses less digits than its factorization.

13125442512502 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6690350.

The product of its (nonzero) digits is 96000, while the sum is 37.

Adding to 13125442512502 its reverse (20521524452131), we get a palindrome (33646966964633).

The spelling of 13125442512502 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-two million, five hundred twelve thousand, five hundred two".

Divisors: 1 2 1194019 2388038 5496329 10992658 6562721256251 13125442512502