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13125442513177 is a prime number
BaseRepresentation
bin1011111100000000000101…
…0101101010100100011001
31201110210001122201110022001
42333000001111222210121
53210021401240410202
643525424533001001
72523165462356221
oct277000125524431
951423048643261
1013125442513177
114200518134595
12157b970183161
137429545a9387
143353bc0dd081
1517b652353d87
hexbf00156a919

13125442513177 has 2 divisors, whose sum is σ = 13125442513178. Its totient is φ = 13125442513176.

The previous prime is 13125442513163. The next prime is 13125442513187. The reversal of 13125442513177 is 77131524452131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9644602291776 + 3480840221401 = 3105576^2 + 1865701^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13125442513177 is a prime.

It is not a weakly prime, because it can be changed into another prime (13125442513187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6562721256588 + 6562721256589.

It is an arithmetic number, because the mean of its divisors is an integer number (6562721256589).

Almost surely, 213125442513177 is an apocalyptic number.

It is an amenable number.

13125442513177 is a deficient number, since it is larger than the sum of its proper divisors (1).

13125442513177 is an equidigital number, since it uses as much as digits as its factorization.

13125442513177 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 705600, while the sum is 46.

The spelling of 13125442513177 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-two million, five hundred thirteen thousand, one hundred seventy-seven".