13125442513241 has 4 divisors (see below), whose sum is σ = 13158174290484. Its totient is φ = 13092710736000.

The previous prime is 13125442513213. The next prime is 13125442513259. The reversal of 13125442513241 is 14231524452131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 12228309610000 + 897132903241 = 3496900^2 + 947171^2 .

It is a cyclic number.

It is not a de Polignac number, because 13125442513241 - 2⁶ = 13125442513177 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13125442513195 and 13125442513204.

It is not an unprimeable number, because it can be changed into a prime (13125442513441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16365888020 + ... + 16365888821.

It is an arithmetic number, because the mean of its divisors is an integer number (3289543572621).

Almost surely, 2^{13125442513241} is an apocalyptic number.

It is an amenable number.

13125442513241 is a deficient number, since it is larger than the sum of its proper divisors (32731777243).

13125442513241 is an equidigital number, since it uses as much as digits as its factorization.

13125442513241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32731777242.

The product of its digits is 115200, while the sum is 38.

Adding to 13125442513241 its reverse (14231524452131), we get a palindrome (27356966965372).

The spelling of 13125442513241 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-two million, five hundred thirteen thousand, two hundred forty-one".