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13125445143542 = 28217993571951
BaseRepresentation
bin1011111100000000000101…
…1111101100101111110110
31201110210001211200002110222
42333000001133230233312
53210021402424043132
643525425105214342
72523165523623014
oct277000137545766
951423054602428
1013125445143542
114200519670846
12157b9710313b2
13742954cba6c4
143353bc5c58b4
1517b6526c3412
hexbf0017ecbf6

13125445143542 has 8 divisors (see below), whose sum is σ = 19712148433632. Its totient is φ = 6554728999000.

The previous prime is 13125445143541. The next prime is 13125445143571. The reversal of 13125445143542 is 24534154452131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×131254451435422 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13125445143493 and 13125445143502.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13125445143541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3996784334 + ... + 3996787617.

It is an arithmetic number, because the mean of its divisors is an integer number (2464018554204).

Almost surely, 213125445143542 is an apocalyptic number.

13125445143542 is a deficient number, since it is larger than the sum of its proper divisors (6586703290090).

13125445143542 is an equidigital number, since it uses as much as digits as its factorization.

13125445143542 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7993572774.

The product of its digits is 1152000, while the sum is 44.

Adding to 13125445143542 its reverse (24534154452131), we get a palindrome (37659599595673).

The spelling of 13125445143542 in words is "thirteen trillion, one hundred twenty-five billion, four hundred forty-five million, one hundred forty-three thousand, five hundred forty-two".

Divisors: 1 2 821 1642 7993571951 15987143902 6562722571771 13125445143542