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13125453101042 = 26562726550521
BaseRepresentation
bin1011111100000000000111…
…1110000011011111110010
31201110210002101122101010012
42333000001332003133302
53210021411443213132
643525425551534522
72523165651354512
oct277000176033762
951423071571105
1013125453101042
114200523106397
12157b97382a442
13742956845699
143353bd697842
1517b6532460b2
hexbf001f837f2

13125453101042 has 4 divisors (see below), whose sum is σ = 19688179651566. Its totient is φ = 6562726550520.

The previous prime is 13125453101021. The next prime is 13125453101051. The reversal of 13125453101042 is 24010135452131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 11548843892881 + 1576609208161 = 3398359^2 + 1255631^2 .

It is a super-2 number, since 2×131254531010422 (a number of 27 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3281363275259 + ... + 3281363275262.

Almost surely, 213125453101042 is an apocalyptic number.

13125453101042 is a deficient number, since it is larger than the sum of its proper divisors (6562726550524).

13125453101042 is an equidigital number, since it uses as much as digits as its factorization.

13125453101042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6562726550523.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 13125453101042 its reverse (24010135452131), we get a palindrome (37135588553173).

The spelling of 13125453101042 in words is "thirteen trillion, one hundred twenty-five billion, four hundred fifty-three million, one hundred one thousand, forty-two".

Divisors: 1 2 6562726550521 13125453101042