Base | Representation |
---|---|
bin | 111101000111101101… |
… | …0000101111110111011 |
3 | 110112210101102220101001 |
4 | 1322033122011332323 |
5 | 4122302240013034 |
6 | 140144150105431 |
7 | 12324423046312 |
oct | 1721732057673 |
9 | 415711386331 |
10 | 131255001019 |
11 | 50735031a5a |
12 | 2153104b277 |
13 | c4b9bb579c |
14 | 64d2035279 |
15 | 3633115a14 |
hex | 1e8f685fbb |
131255001019 has 2 divisors, whose sum is σ = 131255001020. Its totient is φ = 131255001018.
The previous prime is 131255000971. The next prime is 131255001029. The reversal of 131255001019 is 910100552131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131255001019 - 217 = 131254869947 is a prime.
It is a super-2 number, since 2×1312550010192 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131255001029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65627500509 + 65627500510.
It is an arithmetic number, because the mean of its divisors is an integer number (65627500510).
Almost surely, 2131255001019 is an apocalyptic number.
131255001019 is a deficient number, since it is larger than the sum of its proper divisors (1).
131255001019 is an equidigital number, since it uses as much as digits as its factorization.
131255001019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 28.
The spelling of 131255001019 in words is "one hundred thirty-one billion, two hundred fifty-five million, one thousand, nineteen".
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