Base | Representation |
---|---|
bin | 10011000110011010000… |
… | …101011001111100100101 |
3 | 11122110220212122021220221 |
4 | 103012122011121330211 |
5 | 133001100313233131 |
6 | 2442551024324341 |
7 | 163554134024113 |
oct | 23063205317445 |
9 | 4573825567827 |
10 | 1312550133541 |
11 | 466716372289 |
12 | 19246a4736b1 |
13 | 96a0821816a |
14 | 4775628cab3 |
15 | 24220b13411 |
hex | 1319a159f25 |
1312550133541 has 8 divisors (see below), whose sum is σ = 1320632050784. Its totient is φ = 1304468575920.
The previous prime is 1312550133463. The next prime is 1312550133593. The reversal of 1312550133541 is 1453310552131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1312550133541 - 29 = 1312550133029 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1312550133497 and 1312550133506.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1312550103541) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 13944526 + ... + 14038336.
It is an arithmetic number, because the mean of its divisors is an integer number (165079006348).
Almost surely, 21312550133541 is an apocalyptic number.
It is an amenable number.
1312550133541 is a deficient number, since it is larger than the sum of its proper divisors (8081917243).
1312550133541 is an equidigital number, since it uses as much as digits as its factorization.
1312550133541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 179811.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 1312550133541 its reverse (1453310552131), we get a palindrome (2765860685672).
The spelling of 1312550133541 in words is "one trillion, three hundred twelve billion, five hundred fifty million, one hundred thirty-three thousand, five hundred forty-one".
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