Base | Representation |
---|---|
bin | 111101000111111000… |
… | …1000100001111000011 |
3 | 110112210210202212012201 |
4 | 1322033301010033003 |
5 | 4122310310220141 |
6 | 140144523134031 |
7 | 12324525200515 |
oct | 1721761041703 |
9 | 415723685181 |
10 | 131261023171 |
11 | 50738475543 |
12 | 21533074317 |
13 | c4bb2138a5 |
14 | 64d2b61bb5 |
15 | 3633905031 |
hex | 1e8fc443c3 |
131261023171 has 2 divisors, whose sum is σ = 131261023172. Its totient is φ = 131261023170.
The previous prime is 131261023151. The next prime is 131261023247. The reversal of 131261023171 is 171320162131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131261023171 - 213 = 131261014979 is a prime.
It is not a weakly prime, because it can be changed into another prime (131261023141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65630511585 + 65630511586.
It is an arithmetic number, because the mean of its divisors is an integer number (65630511586).
Almost surely, 2131261023171 is an apocalyptic number.
131261023171 is a deficient number, since it is larger than the sum of its proper divisors (1).
131261023171 is an equidigital number, since it uses as much as digits as its factorization.
131261023171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 28.
The spelling of 131261023171 in words is "one hundred thirty-one billion, two hundred sixty-one million, twenty-three thousand, one hundred seventy-one".
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