Base | Representation |
---|---|
bin | 1011111100000011110001… |
… | …1010110000000111010001 |
3 | 1201110212121201211002020021 |
4 | 2333000330122300013101 |
5 | 3210030414011433403 |
6 | 43530111141343441 |
7 | 2523232156342456 |
oct | 277007432600721 |
9 | 51425551732207 |
10 | 13126433702353 |
11 | 420098668a6a4 |
12 | 157bba8107b81 |
13 | 742a81a5004a |
14 | 3354739d582d |
15 | 17b6ae3948bd |
hex | bf03c6b01d1 |
13126433702353 has 2 divisors, whose sum is σ = 13126433702354. Its totient is φ = 13126433702352.
The previous prime is 13126433702341. The next prime is 13126433702399. The reversal of 13126433702353 is 35320733462131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9856441413009 + 3269992289344 = 3139497^2 + 1808312^2 .
It is a cyclic number.
It is not a de Polignac number, because 13126433702353 - 213 = 13126433694161 is a prime.
It is not a weakly prime, because it can be changed into another prime (13126403702353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563216851176 + 6563216851177.
It is an arithmetic number, because the mean of its divisors is an integer number (6563216851177).
Almost surely, 213126433702353 is an apocalyptic number.
It is an amenable number.
13126433702353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13126433702353 is an equidigital number, since it uses as much as digits as its factorization.
13126433702353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 816480, while the sum is 43.
The spelling of 13126433702353 in words is "thirteen trillion, one hundred twenty-six billion, four hundred thirty-three million, seven hundred two thousand, three hundred fifty-three".
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