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1312698403 is a prime number
BaseRepresentation
bin100111000111110…
…0011000000100011
310101111001222200101
41032033203000203
510142022322103
6334131403231
744346516022
oct11617430043
93344058611
101312698403
11613a90815
12307753517
1317bc62b23
14c64a88b9
157a39ca1d
hex4e3e3023

1312698403 has 2 divisors, whose sum is σ = 1312698404. Its totient is φ = 1312698402.

The previous prime is 1312698377. The next prime is 1312698407. The reversal of 1312698403 is 3048962131.

It is a strong prime.

It is an emirp because it is prime and its reverse (3048962131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1312698403 is a prime.

It is not a weakly prime, because it can be changed into another prime (1312698407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656349201 + 656349202.

It is an arithmetic number, because the mean of its divisors is an integer number (656349202).

Almost surely, 21312698403 is an apocalyptic number.

1312698403 is a deficient number, since it is larger than the sum of its proper divisors (1).

1312698403 is an equidigital number, since it uses as much as digits as its factorization.

1312698403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 37.

The square root of 1312698403 is about 36231.1799835446. The cubic root of 1312698403 is about 1094.9349510645.

The spelling of 1312698403 in words is "one billion, three hundred twelve million, six hundred ninety-eight thousand, four hundred three".