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13127293745281 is a prime number
BaseRepresentation
bin1011111100000110111110…
…1011100011100010000001
31201110221211200010210100001
42333001233223203202001
53210034144144322111
643530332343200001
72523262401522322
oct277015753434201
951427750123301
1013127293745281
114201288100681
1215801a8146001
13742b8ac965a1
14335515d10449
1517b70eb2c1c1
hexbf06fae3881

13127293745281 has 2 divisors, whose sum is σ = 13127293745282. Its totient is φ = 13127293745280.

The previous prime is 13127293745243. The next prime is 13127293745297. The reversal of 13127293745281 is 18254739272131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11828206694656 + 1299087050625 = 3439216^2 + 1139775^2 .

It is a cyclic number.

It is not a de Polignac number, because 13127293745281 - 211 = 13127293743233 is a prime.

It is a super-2 number, since 2×131272937452812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13127293745221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563646872640 + 6563646872641.

It is an arithmetic number, because the mean of its divisors is an integer number (6563646872641).

Almost surely, 213127293745281 is an apocalyptic number.

It is an amenable number.

13127293745281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13127293745281 is an equidigital number, since it uses as much as digits as its factorization.

13127293745281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5080320, while the sum is 55.

The spelling of 13127293745281 in words is "thirteen trillion, one hundred twenty-seven billion, two hundred ninety-three million, seven hundred forty-five thousand, two hundred eighty-one".