13127420111401 has 2 divisors, whose sum is σ = 13127420111402. Its totient is φ = 13127420111400.

The previous prime is 13127420111353. The next prime is 13127420111419. The reversal of 13127420111401 is 10411102472131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12685030176025 + 442389935376 = 3561605^2 + 665124^2 .

It is an emirp because it is prime and its reverse (10411102472131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13127420111401 - 2³⁵ = 13093060373033 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13127420111401.

It is not a weakly prime, because it can be changed into another prime (13127420111431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6563710055700 + 6563710055701.

It is an arithmetic number, because the mean of its divisors is an integer number (6563710055701).

Almost surely, 2^{13127420111401} is an apocalyptic number.

It is an amenable number.

13127420111401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13127420111401 is an equidigital number, since it uses as much as digits as its factorization.

13127420111401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 28.

Adding to 13127420111401 its reverse (10411102472131), we get a palindrome (23538522583532).

The spelling of 13127420111401 in words is "thirteen trillion, one hundred twenty-seven billion, four hundred twenty million, one hundred eleven thousand, four hundred one".