Base | Representation |
---|---|
bin | 111101001000010011… |
… | …0111001000101110110 |
3 | 110112211210022201200011 |
4 | 1322100212321011312 |
5 | 4122322413231202 |
6 | 140150145410434 |
7 | 12325056136105 |
oct | 1722046710566 |
9 | 415753281604 |
10 | 131275133302 |
11 | 50745432705 |
12 | 21537939a1a |
13 | c4c1114191 |
14 | 64d499603c |
15 | 3634c90bd7 |
hex | 1e909b9176 |
131275133302 has 4 divisors (see below), whose sum is σ = 196912699956. Its totient is φ = 65637566650.
The previous prime is 131275133299. The next prime is 131275133303. The reversal of 131275133302 is 203331572131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 203331572131 = 14251 ⋅14267881.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131275133303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32818783324 + ... + 32818783327.
It is an arithmetic number, because the mean of its divisors is an integer number (49228174989).
Almost surely, 2131275133302 is an apocalyptic number.
131275133302 is a deficient number, since it is larger than the sum of its proper divisors (65637566654).
131275133302 is an equidigital number, since it uses as much as digits as its factorization.
131275133302 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65637566653.
The product of its (nonzero) digits is 11340, while the sum is 31.
The spelling of 131275133302 in words is "one hundred thirty-one billion, two hundred seventy-five million, one hundred thirty-three thousand, three hundred two".
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