Base | Representation |
---|---|
bin | 11000011101000101… |
… | …10010001011101110 |
3 | 1020212222100021212212 |
4 | 30032202302023232 |
5 | 203341444320413 |
6 | 10010433530422 |
7 | 643226551226 |
oct | 141642621356 |
9 | 36788307785 |
10 | 13128901358 |
11 | 5627a16a01 |
12 | 2664a13a12 |
13 | 1312cc43b1 |
14 | 8c7921086 |
15 | 51c914ca8 |
hex | 30e8b22ee |
13128901358 has 4 divisors (see below), whose sum is σ = 19693352040. Its totient is φ = 6564450678.
The previous prime is 13128901349. The next prime is 13128901361. The reversal of 13128901358 is 85310982131.
13128901358 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 85310982131 = 187973 ⋅453847.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282225338 + ... + 3282225341.
It is an arithmetic number, because the mean of its divisors is an integer number (4923338010).
Almost surely, 213128901358 is an apocalyptic number.
13128901358 is a deficient number, since it is larger than the sum of its proper divisors (6564450682).
13128901358 is an equidigital number, since it uses as much as digits as its factorization.
13128901358 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6564450681.
The product of its (nonzero) digits is 51840, while the sum is 41.
The spelling of 13128901358 in words is "thirteen billion, one hundred twenty-eight million, nine hundred one thousand, three hundred fifty-eight".
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