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131300072143 = 1021128599483
BaseRepresentation
bin111101001001000011…
…0000001101011001111
3110112220112020202022221
41322102012001223033
54122400304302033
6140152440120211
712325511125102
oct1722206015317
9415815222287
10131300072143
1150758516619
1221544166067
13c4c63365a6
1464d8008739
15363706a12d
hex1e92181acf

131300072143 has 4 divisors (see below), whose sum is σ = 131428672648. Its totient is φ = 131171471640.

The previous prime is 131300072129. The next prime is 131300072171. The reversal of 131300072143 is 341270003131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131300072143 - 233 = 122710137551 is a prime.

It is a super-2 number, since 2×1313000721432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131300072243) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64298721 + ... + 64300762.

It is an arithmetic number, because the mean of its divisors is an integer number (32857168162).

Almost surely, 2131300072143 is an apocalyptic number.

131300072143 is a deficient number, since it is larger than the sum of its proper divisors (128600505).

131300072143 is a wasteful number, since it uses less digits than its factorization.

131300072143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 128600504.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 131300072143 its reverse (341270003131), we get a palindrome (472570075274).

The spelling of 131300072143 in words is "one hundred thirty-one billion, three hundred million, seventy-two thousand, one hundred forty-three".

Divisors: 1 1021 128599483 131300072143