Base | Representation |
---|---|
bin | 1011111100010001000110… |
… | …0110110110011111110010 |
3 | 1201111012212000001020010221 |
4 | 2333010101212312133302 |
5 | 3210110230131434414 |
6 | 43531502111043254 |
7 | 2523416620061350 |
oct | 277042146663762 |
9 | 51435760036127 |
10 | 13130010421234 |
11 | 4202451647513 |
12 | 1580825b1052a |
13 | 743201a6b455 |
14 | 3356d2a447d0 |
15 | 17b81d3a8224 |
hex | bf1119b67f2 |
13130010421234 has 16 divisors (see below), whose sum is σ = 22531770150336. Its totient is φ = 5621352109200.
The previous prime is 13130010421217. The next prime is 13130010421237. The reversal of 13130010421234 is 43212401003131.
It is a junction number, because it is equal to n+sod(n) for n = 13130010421199 and 13130010421208.
It is not an unprimeable number, because it can be changed into a prime (13130010421237) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 482920437 + ... + 482947624.
It is an arithmetic number, because the mean of its divisors is an integer number (1408235634396).
Almost surely, 213130010421234 is an apocalyptic number.
13130010421234 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
13130010421234 is a deficient number, since it is larger than the sum of its proper divisors (9401759729102).
13130010421234 is an equidigital number, since it uses as much as digits as its factorization.
13130010421234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 965869041.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13130010421234 its reverse (43212401003131), we get a palindrome (56342411424365).
The spelling of 13130010421234 in words is "thirteen trillion, one hundred thirty billion, ten million, four hundred twenty-one thousand, two hundred thirty-four".
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