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13130010421234 = 27971965868061
BaseRepresentation
bin1011111100010001000110…
…0110110110011111110010
31201111012212000001020010221
42333010101212312133302
53210110230131434414
643531502111043254
72523416620061350
oct277042146663762
951435760036127
1013130010421234
114202451647513
121580825b1052a
13743201a6b455
143356d2a447d0
1517b81d3a8224
hexbf1119b67f2

13130010421234 has 16 divisors (see below), whose sum is σ = 22531770150336. Its totient is φ = 5621352109200.

The previous prime is 13130010421217. The next prime is 13130010421237. The reversal of 13130010421234 is 43212401003131.

It is a junction number, because it is equal to n+sod(n) for n = 13130010421199 and 13130010421208.

It is not an unprimeable number, because it can be changed into a prime (13130010421237) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 482920437 + ... + 482947624.

It is an arithmetic number, because the mean of its divisors is an integer number (1408235634396).

Almost surely, 213130010421234 is an apocalyptic number.

13130010421234 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

13130010421234 is a deficient number, since it is larger than the sum of its proper divisors (9401759729102).

13130010421234 is an equidigital number, since it uses as much as digits as its factorization.

13130010421234 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 965869041.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13130010421234 its reverse (43212401003131), we get a palindrome (56342411424365).

The spelling of 13130010421234 in words is "thirteen trillion, one hundred thirty billion, ten million, four hundred twenty-one thousand, two hundred thirty-four".

Divisors: 1 2 7 14 971 1942 6797 13594 965868061 1931736122 6761076427 13522152854 937857887231 1875715774462 6565005210617 13130010421234