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131300113222 = 265650056611
BaseRepresentation
bin111101001001000011…
…0001011101101000110
3110112220112022211200101
41322102012023231012
54122400312110342
6140152441034314
712325511355625
oct1722206135506
9415815284611
10131300113222
1150758544473
122154418599a
13c4c634c1b5
1464d80196bc
1536370773b7
hex1e9218bb46

131300113222 has 4 divisors (see below), whose sum is σ = 196950169836. Its totient is φ = 65650056610.

The previous prime is 131300113211. The next prime is 131300113223. The reversal of 131300113222 is 222311003131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 222311003131 = 731758714733.

It is a super-2 number, since 2×1313001132222 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 131300113222.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131300113223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32825028304 + ... + 32825028307.

It is an arithmetic number, because the mean of its divisors is an integer number (49237542459).

Almost surely, 2131300113222 is an apocalyptic number.

131300113222 is a deficient number, since it is larger than the sum of its proper divisors (65650056614).

131300113222 is an equidigital number, since it uses as much as digits as its factorization.

131300113222 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65650056613.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 131300113222 its reverse (222311003131), we get a palindrome (353611116353).

The spelling of 131300113222 in words is "one hundred thirty-one billion, three hundred million, one hundred thirteen thousand, two hundred twenty-two".

Divisors: 1 2 65650056611 131300113222