Base | Representation |
---|---|
bin | 10011000110110100111… |
… | …110001010011110110110 |
3 | 11122112002022102212020122 |
4 | 103012310332022132312 |
5 | 133003011303020042 |
6 | 2443103500531542 |
7 | 163601252140052 |
oct | 23066476123666 |
9 | 4575068385218 |
10 | 1313001220022 |
11 | 466927a60228 |
12 | 192575550bb2 |
13 | 96a7a80553b |
14 | 4779a150c62 |
15 | 2424a5187d2 |
hex | 131b4f8a7b6 |
1313001220022 has 4 divisors (see below), whose sum is σ = 1969501830036. Its totient is φ = 656500610010.
The previous prime is 1313001220009. The next prime is 1313001220039. The reversal of 1313001220022 is 2200221003131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 328250305004 + ... + 328250305007.
It is an arithmetic number, because the mean of its divisors is an integer number (492375457509).
Almost surely, 21313001220022 is an apocalyptic number.
1313001220022 is a deficient number, since it is larger than the sum of its proper divisors (656500610014).
1313001220022 is an equidigital number, since it uses as much as digits as its factorization.
1313001220022 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 656500610013.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 1313001220022 its reverse (2200221003131), we get a palindrome (3513222223153).
The spelling of 1313001220022 in words is "one trillion, three hundred thirteen billion, one million, two hundred twenty thousand, twenty-two".
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