Base | Representation |
---|---|
bin | 10011000110110101000… |
… | …011000011000011101111 |
3 | 11122112002101211220111122 |
4 | 103012311003003003233 |
5 | 133003012120002320 |
6 | 2443103544211155 |
7 | 163601266051541 |
oct | 23066503030357 |
9 | 4575071756448 |
10 | 1313002500335 |
11 | 466928755139 |
12 | 192575a69abb |
13 | 96a7ab63216 |
14 | 4779a3a5691 |
15 | 2424a6bcd25 |
hex | 131b50c30ef |
1313002500335 has 16 divisors (see below), whose sum is σ = 1591125120000. Its totient is φ = 1040063759136.
The previous prime is 1313002500301. The next prime is 1313002500379. The reversal of 1313002500335 is 5330052003131.
It is not a de Polignac number, because 1313002500335 - 220 = 1313001451759 is a prime.
It is a super-2 number, since 2×13130025003352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 455606 + ... + 1683324.
It is an arithmetic number, because the mean of its divisors is an integer number (99445320000).
Almost surely, 21313002500335 is an apocalyptic number.
1313002500335 is a deficient number, since it is larger than the sum of its proper divisors (278122619665).
1313002500335 is a wasteful number, since it uses less digits than its factorization.
1313002500335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1229830.
The product of its (nonzero) digits is 4050, while the sum is 26.
Adding to 1313002500335 its reverse (5330052003131), we get a palindrome (6643054503466).
The spelling of 1313002500335 in words is "one trillion, three hundred thirteen billion, two million, five hundred thousand, three hundred thirty-five".
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