Base | Representation |
---|---|
bin | 10011000110110101000… |
… | …101110011010011010011 |
3 | 11122112002110012120202101 |
4 | 103012311011303103103 |
5 | 133003012311102402 |
6 | 2443104011501231 |
7 | 163601305146304 |
oct | 23066505632323 |
9 | 4575073176671 |
10 | 1313003222227 |
11 | 4669290a8544 |
12 | 192576157817 |
13 | 96a7b056988 |
14 | 4779a5127ab |
15 | 2424a7b1b87 |
hex | 131b51734d3 |
1313003222227 has 2 divisors, whose sum is σ = 1313003222228. Its totient is φ = 1313003222226.
The previous prime is 1313003222147. The next prime is 1313003222239. The reversal of 1313003222227 is 7222223003131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1313003222227 - 219 = 1313002697939 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313003222195 and 1313003222204.
It is not a weakly prime, because it can be changed into another prime (1313003222327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656501611113 + 656501611114.
It is an arithmetic number, because the mean of its divisors is an integer number (656501611114).
Almost surely, 21313003222227 is an apocalyptic number.
1313003222227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313003222227 is an equidigital number, since it uses as much as digits as its factorization.
1313003222227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 1313003222227 its reverse (7222223003131), we get a palindrome (8535226225358).
The spelling of 1313003222227 in words is "one trillion, three hundred thirteen billion, three million, two hundred twenty-two thousand, two hundred twenty-seven".
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