Base | Representation |
---|---|
bin | 11000011101001110… |
… | …00110010010101101 |
3 | 1020220001110202020122 |
4 | 30032213012102231 |
5 | 203342242013201 |
6 | 10010514054325 |
7 | 643242301361 |
oct | 141647062255 |
9 | 36801422218 |
10 | 13130032301 |
11 | 5628619671 |
12 | 266527a3a5 |
13 | 13132cc0a9 |
14 | 8c7b372a1 |
15 | 51ca89e1b |
hex | 30e9c64ad |
13130032301 has 4 divisors (see below), whose sum is σ = 13178843100. Its totient is φ = 13081221504.
The previous prime is 13130032273. The next prime is 13130032309. The reversal of 13130032301 is 10323003131.
13130032301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5578596100 + 7551436201 = 74690^2 + 86899^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130032301 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 13130032301.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13130032309) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24404996 + ... + 24405533.
It is an arithmetic number, because the mean of its divisors is an integer number (3294710775).
Almost surely, 213130032301 is an apocalyptic number.
It is an amenable number.
13130032301 is a deficient number, since it is larger than the sum of its proper divisors (48810799).
13130032301 is an equidigital number, since it uses as much as digits as its factorization.
13130032301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48810798.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 13130032301 its reverse (10323003131), we get a palindrome (23453035432).
The spelling of 13130032301 in words is "thirteen billion, one hundred thirty million, thirty-two thousand, three hundred one".
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