Base | Representation |
---|---|
bin | 11101110110101011000011… |
… | …101011010010010100111110 |
3 | 122012220012100221101200122002 |
4 | 131312223003223102110332 |
5 | 114202211241341034402 |
6 | 1143130330345222302 |
7 | 36441100064064056 |
oct | 3566530353222476 |
9 | 565805327350562 |
10 | 131300433143102 |
11 | 38922223572223 |
12 | 12886aa1491992 |
13 | 5835768326702 |
14 | 245cd91098566 |
15 | 102a65b52c602 |
hex | 776ac3ad253e |
131300433143102 has 4 divisors (see below), whose sum is σ = 196950649714656. Its totient is φ = 65650216571550.
The previous prime is 131300433143059. The next prime is 131300433143111. The reversal of 131300433143102 is 201341334003131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32825108285774 + ... + 32825108285777.
It is an arithmetic number, because the mean of its divisors is an integer number (49237662428664).
Almost surely, 2131300433143102 is an apocalyptic number.
131300433143102 is a deficient number, since it is larger than the sum of its proper divisors (65650216571554).
131300433143102 is an equidigital number, since it uses as much as digits as its factorization.
131300433143102 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65650216571553.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 131300433143102 its reverse (201341334003131), we get a palindrome (332641767146233).
The spelling of 131300433143102 in words is "one hundred thirty-one trillion, three hundred billion, four hundred thirty-three million, one hundred forty-three thousand, one hundred two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •