Base | Representation |
---|---|
bin | 11000011101001110… |
… | …10110111011010001 |
3 | 1020220001121012201001 |
4 | 30032213112323101 |
5 | 203342301203213 |
6 | 10010515342001 |
7 | 643243004122 |
oct | 141647267321 |
9 | 36801535631 |
10 | 13130100433 |
11 | 562866587a |
12 | 26652b1901 |
13 | 13133240c8 |
14 | 8c7b54049 |
15 | 51caa01dd |
hex | 30e9d6ed1 |
13130100433 has 32 divisors (see below), whose sum is σ = 14472691200. Its totient is φ = 11863425024.
The previous prime is 13130100419. The next prime is 13130100443. The reversal of 13130100433 is 33400103131.
It is a cyclic number.
It is not a de Polignac number, because 13130100433 - 221 = 13128003281 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13130100433.
It is not an unprimeable number, because it can be changed into a prime (13130100443) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 9318033 + ... + 9319441.
It is an arithmetic number, because the mean of its divisors is an integer number (452271600).
Almost surely, 213130100433 is an apocalyptic number.
It is an amenable number.
13130100433 is a deficient number, since it is larger than the sum of its proper divisors (1342590767).
13130100433 is a wasteful number, since it uses less digits than its factorization.
13130100433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1689.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 13130100433 its reverse (33400103131), we get a palindrome (46530203564).
The spelling of 13130100433 in words is "thirteen billion, one hundred thirty million, one hundred thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •