Base | Representation |
---|---|
bin | 111101001001000100… |
… | …1101100000011000011 |
3 | 110112220121001112012001 |
4 | 1322102021230003003 |
5 | 4122401031012011 |
6 | 140152512444431 |
7 | 12325522233643 |
oct | 1722211540303 |
9 | 415817045161 |
10 | 131301032131 |
11 | 507590118a5 |
12 | 21544549717 |
13 | c4c65b1529 |
14 | 64d81b8523 |
15 | 36371a97c1 |
hex | 1e9226c0c3 |
131301032131 has 2 divisors, whose sum is σ = 131301032132. Its totient is φ = 131301032130.
The previous prime is 131301032117. The next prime is 131301032147. The reversal of 131301032131 is 131230103131.
It is a weak prime.
It is an emirp because it is prime and its reverse (131230103131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131301032131 - 221 = 131298934979 is a prime.
It is a super-2 number, since 2×1313010321312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 131301032099 and 131301032108.
It is not a weakly prime, because it can be changed into another prime (131301012131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650516065 + 65650516066.
It is an arithmetic number, because the mean of its divisors is an integer number (65650516066).
Almost surely, 2131301032131 is an apocalyptic number.
131301032131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301032131 is an equidigital number, since it uses as much as digits as its factorization.
131301032131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 131301032131 its reverse (131230103131), we get a palindrome (262531135262).
The spelling of 131301032131 in words is "one hundred thirty-one billion, three hundred one million, thirty-two thousand, one hundred thirty-one".
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