13130114004329 has 4 divisors (see below), whose sum is σ = 15005844576384. Its totient is φ = 11254383432276.

The previous prime is 13130114004311. The next prime is 13130114004361. The reversal of 13130114004329 is 92340041103131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13130114004329 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13130114004295 and 13130114004304.

It is not an unprimeable number, because it can be changed into a prime (13130114004529) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 937865286017 + ... + 937865286030.

It is an arithmetic number, because the mean of its divisors is an integer number (3751461144096).

Almost surely, 2^{13130114004329} is an apocalyptic number.

It is an amenable number.

13130114004329 is a deficient number, since it is larger than the sum of its proper divisors (1875730572055).

13130114004329 is an equidigital number, since it uses as much as digits as its factorization.

13130114004329 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1875730572054.

The product of its (nonzero) digits is 7776, while the sum is 32.

The spelling of 13130114004329 in words is "thirteen trillion, one hundred thirty billion, one hundred fourteen million, four thousand, three hundred twenty-nine".