Base | Representation |
---|---|
bin | 1011111100010001011111… |
… | …0001111111010101010111 |
3 | 1201111020010012221210102012 |
4 | 2333010113301333111113 |
5 | 3210110433141114221 |
6 | 43531520251134435 |
7 | 2523422315366003 |
oct | 277042761772527 |
9 | 51436105853365 |
10 | 13130114004311 |
11 | 42024a5065a67 |
12 | 158085474441b |
13 | 74321a367b05 |
14 | 3357026c9703 |
15 | 17b82751965b |
hex | bf117c7f557 |
13130114004311 has 2 divisors, whose sum is σ = 13130114004312. Its totient is φ = 13130114004310.
The previous prime is 13130114004299. The next prime is 13130114004361. The reversal of 13130114004311 is 11340041103131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13130114004311 - 26 = 13130114004247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13130114004361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565057002155 + 6565057002156.
It is an arithmetic number, because the mean of its divisors is an integer number (6565057002156).
Almost surely, 213130114004311 is an apocalyptic number.
13130114004311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130114004311 is an equidigital number, since it uses as much as digits as its factorization.
13130114004311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13130114004311 its reverse (11340041103131), we get a palindrome (24470155107442).
The spelling of 13130114004311 in words is "thirteen trillion, one hundred thirty billion, one hundred fourteen million, four thousand, three hundred eleven".
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