Base | Representation |
---|---|
bin | 11101110110101011111000… |
… | …100011010010111110110001 |
3 | 122012220021122202121221021111 |
4 | 131312223320203102332301 |
5 | 114202220100440203243 |
6 | 1143130554354553321 |
7 | 36441131055225403 |
oct | 3566537043227661 |
9 | 565807582557244 |
10 | 131301320241073 |
11 | 38922639292044 |
12 | 128870aa598841 |
13 | 583587a053658 |
14 | 245d036c16b73 |
15 | 102a6ae35b39d |
hex | 776af88d2fb1 |
131301320241073 has 2 divisors, whose sum is σ = 131301320241074. Its totient is φ = 131301320241072.
The previous prime is 131301320241061. The next prime is 131301320241089. The reversal of 131301320241073 is 370142023103131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 110493061818624 + 20808258422449 = 10511568^2 + 4561607^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131301320241073 is a prime.
It is not a weakly prime, because it can be changed into another prime (131301320241023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65650660120536 + 65650660120537.
It is an arithmetic number, because the mean of its divisors is an integer number (65650660120537).
Almost surely, 2131301320241073 is an apocalyptic number.
It is an amenable number.
131301320241073 is a deficient number, since it is larger than the sum of its proper divisors (1).
131301320241073 is an equidigital number, since it uses as much as digits as its factorization.
131301320241073 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
The spelling of 131301320241073 in words is "one hundred thirty-one trillion, three hundred one billion, three hundred twenty million, two hundred forty-one thousand, seventy-three".
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