Base | Representation |
---|---|
bin | 1011111100010001100110… |
… | …0000100110101000011001 |
3 | 1201111020012020111222112211 |
4 | 2333010121200212220121 |
5 | 3210111013102013423 |
6 | 43531523204435121 |
7 | 2523423120015535 |
oct | 277043140465031 |
9 | 51436166458484 |
10 | 13130143001113 |
11 | 420250a470766 |
12 | 15808623a8aa1 |
13 | 74322337b298 |
14 | 3357064b6bc5 |
15 | 17b829d4610d |
hex | bf119826a19 |
13130143001113 has 2 divisors, whose sum is σ = 13130143001114. Its totient is φ = 13130143001112.
The previous prime is 13130143001071. The next prime is 13130143001201. The reversal of 13130143001113 is 31110034103131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7989820197129 + 5140322803984 = 2826627^2 + 2267228^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130143001113 is a prime.
It is not a weakly prime, because it can be changed into another prime (13130143001513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565071500556 + 6565071500557.
It is an arithmetic number, because the mean of its divisors is an integer number (6565071500557).
Almost surely, 213130143001113 is an apocalyptic number.
It is an amenable number.
13130143001113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130143001113 is an equidigital number, since it uses as much as digits as its factorization.
13130143001113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13130143001113 its reverse (31110034103131), we get a palindrome (44240177104244).
The spelling of 13130143001113 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-three million, one thousand, one hundred thirteen".
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