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13130143597913 is a prime number
BaseRepresentation
bin1011111100010001100110…
…0010111000010101011001
31201111020012021122022012112
42333010121202320111121
53210111013230113123
643531523225322105
72523423125052506
oct277043142702531
951436167568175
1013130143597913
11420250a839091
121580862636335
13743223529b14
143357065d04ad
1517b829e12d78
hexbf1198b8559

13130143597913 has 2 divisors, whose sum is σ = 13130143597914. Its totient is φ = 13130143597912.

The previous prime is 13130143597877. The next prime is 13130143597937. The reversal of 13130143597913 is 31979534103131.

13130143597913 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13120818219289 + 9325378624 = 3622267^2 + 96568^2 .

It is a cyclic number.

It is not a de Polignac number, because 13130143597913 - 26 = 13130143597849 is a prime.

It is not a weakly prime, because it can be changed into another prime (13130143591913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565071798956 + 6565071798957.

It is an arithmetic number, because the mean of its divisors is an integer number (6565071798957).

Almost surely, 213130143597913 is an apocalyptic number.

It is an amenable number.

13130143597913 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130143597913 is an equidigital number, since it uses as much as digits as its factorization.

13130143597913 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 918540, while the sum is 50.

The spelling of 13130143597913 in words is "thirteen trillion, one hundred thirty billion, one hundred forty-three million, five hundred ninety-seven thousand, nine hundred thirteen".