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1313017719449 is a prime number
BaseRepresentation
bin10011000110110101111…
…101000110101010011001
311122112010110111010012112
4103012311331012222121
5133003030014010244
62443105250322105
7163601542316252
oct23066575065231
94575113433175
101313017719449
114669362aa517
1219257ab89335
1396a81061507
144779c407b29
152424bbc739e
hex131b5f46a99

1313017719449 has 2 divisors, whose sum is σ = 1313017719450. Its totient is φ = 1313017719448.

The previous prime is 1313017719347. The next prime is 1313017719557. The reversal of 1313017719449 is 9449177103131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1305397651600 + 7620067849 = 1142540^2 + 87293^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313017719449 - 224 = 1313000942233 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313017719397 and 1313017719406.

It is not a weakly prime, because it can be changed into another prime (1313017719149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656508859724 + 656508859725.

It is an arithmetic number, because the mean of its divisors is an integer number (656508859725).

Almost surely, 21313017719449 is an apocalyptic number.

It is an amenable number.

1313017719449 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313017719449 is an equidigital number, since it uses as much as digits as its factorization.

1313017719449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 571536, while the sum is 50.

The spelling of 1313017719449 in words is "one trillion, three hundred thirteen billion, seventeen million, seven hundred nineteen thousand, four hundred forty-nine".