Base | Representation |
---|---|
bin | 111101001001000110… |
… | …1011000101010101011 |
3 | 110112220122212202200001 |
4 | 1322102031120222223 |
5 | 4122401303020243 |
6 | 140152545323431 |
7 | 12325533411403 |
oct | 1722215305253 |
9 | 415818782601 |
10 | 131302001323 |
11 | 50759613a89 |
12 | 21544936577 |
13 | c4c686070c |
14 | 64d838b803 |
15 | 36372eba4d |
hex | 1e92358aab |
131302001323 has 2 divisors, whose sum is σ = 131302001324. Its totient is φ = 131302001322.
The previous prime is 131302001219. The next prime is 131302001359. The reversal of 131302001323 is 323100203131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131302001323 - 217 = 131301870251 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131302001323.
It is not a weakly prime, because it can be changed into another prime (131302002323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651000661 + 65651000662.
It is an arithmetic number, because the mean of its divisors is an integer number (65651000662).
Almost surely, 2131302001323 is an apocalyptic number.
131302001323 is a deficient number, since it is larger than the sum of its proper divisors (1).
131302001323 is an equidigital number, since it uses as much as digits as its factorization.
131302001323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 131302001323 its reverse (323100203131), we get a palindrome (454402204454).
The spelling of 131302001323 in words is "one hundred thirty-one billion, three hundred two million, one thousand, three hundred twenty-three".
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