13130244110020 has 12 divisors (see below), whose sum is σ = 27573512631084. Its totient is φ = 5252097644000.

The previous prime is 13130244110017. The next prime is 13130244110069. The reversal of 13130244110020 is 2001144203131.

It can be written as a sum of positive squares in 2 ways, for example, as 10473663580416 + 2656580529604 = 3236304^2 + 1629902^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13130244109973 and 13130244110000.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 328256102731 + ... + 328256102770.

It is an arithmetic number, because the mean of its divisors is an integer number (2297792719257).

Almost surely, 2^{13130244110020} is an apocalyptic number.

13130244110020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13130244110020 is an abundant number, since it is smaller than the sum of its proper divisors (14443268521064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13130244110020 is a wasteful number, since it uses less digits than its factorization.

13130244110020 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 656512205510 (or 656512205508 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13130244110020 its reverse (2001144203131), we get a palindrome (15131388313151).

The spelling of 13130244110020 in words is "thirteen trillion, one hundred thirty billion, two hundred forty-four million, one hundred ten thousand, twenty".