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13130244424042 = 244501147527521
BaseRepresentation
bin1011111100010001111110…
…0011100000000101101010
31201111020110022100210122121
42333010133203200011222
53210111220033032132
643531541230341454
72523425461055314
oct277043743400552
951436408323577
1013130244424042
114202561744269
12158089035a88a
1374323b39c655
14335715b587b4
1517b833bcc497
hexbf11f8e016a

13130244424042 has 8 divisors (see below), whose sum is σ = 19695809352132. Its totient is φ = 6564974640000.

The previous prime is 13130244424009. The next prime is 13130244424091. The reversal of 13130244424042 is 24042444203131.

13130244424042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 11078506176721 + 2051738247321 = 3328439^2 + 1432389^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13130244423989 and 13130244424007.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 73674759 + ... + 73852762.

Almost surely, 213130244424042 is an apocalyptic number.

13130244424042 is a deficient number, since it is larger than the sum of its proper divisors (6565564928090).

13130244424042 is a wasteful number, since it uses less digits than its factorization.

13130244424042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 147572024.

The product of its (nonzero) digits is 73728, while the sum is 34.

Adding to 13130244424042 its reverse (24042444203131), we get a palindrome (37172688627173).

The spelling of 13130244424042 in words is "thirteen trillion, one hundred thirty billion, two hundred forty-four million, four hundred twenty-four thousand, forty-two".

Divisors: 1 2 44501 89002 147527521 295055042 6565122212021 13130244424042