Base | Representation |
---|---|
bin | 1011111100010010001011… |
… | …0111110101000101110001 |
3 | 1201111020121012002122120111 |
4 | 2333010202313311011301 |
5 | 3210111323310201333 |
6 | 43531550535341321 |
7 | 2523430035140056 |
oct | 277044267650561 |
9 | 51436535078514 |
10 | 13130300084593 |
11 | 420259010091a |
12 | 15808a6b21841 |
13 | 743249a8a3a3 |
14 | 33571d2c702d |
15 | 17b838a244cd |
hex | bf122df5171 |
13130300084593 has 2 divisors, whose sum is σ = 13130300084594. Its totient is φ = 13130300084592.
The previous prime is 13130300084581. The next prime is 13130300084597. The reversal of 13130300084593 is 39548000303131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9234445225329 + 3895854859264 = 3038823^2 + 1973792^2 .
It is an emirp because it is prime and its reverse (39548000303131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13130300084593 is a prime.
It is a super-2 number, since 2×131303000845932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13130300084597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565150042296 + 6565150042297.
It is an arithmetic number, because the mean of its divisors is an integer number (6565150042297).
Almost surely, 213130300084593 is an apocalyptic number.
It is an amenable number.
13130300084593 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130300084593 is an equidigital number, since it uses as much as digits as its factorization.
13130300084593 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 116640, while the sum is 40.
The spelling of 13130300084593 in words is "thirteen trillion, one hundred thirty billion, three hundred million, eighty-four thousand, five hundred ninety-three".
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