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13130302161793 is a prime number
BaseRepresentation
bin1011111100010010001011…
…1111110000001110000001
31201111020121100000011221211
42333010202333300032001
53210111324323134133
643531551052050121
72523430061611045
oct277044277601601
951436540004854
1013130302161793
11420259129a513
1215808a7763941
1374324a3369bb
1433571d6a8025
1517b838cd4bcd
hexbf122ff0381

13130302161793 has 2 divisors, whose sum is σ = 13130302161794. Its totient is φ = 13130302161792.

The previous prime is 13130302161679. The next prime is 13130302161857. The reversal of 13130302161793 is 39716120303131.

13130302161793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11305511842689 + 1824790319104 = 3362367^2 + 1350848^2 .

It is a cyclic number.

It is not a de Polignac number, because 13130302161793 - 229 = 13129765290881 is a prime.

It is not a weakly prime, because it can be changed into another prime (13130302161593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565151080896 + 6565151080897.

It is an arithmetic number, because the mean of its divisors is an integer number (6565151080897).

Almost surely, 213130302161793 is an apocalyptic number.

It is an amenable number.

13130302161793 is a deficient number, since it is larger than the sum of its proper divisors (1).

13130302161793 is an equidigital number, since it uses as much as digits as its factorization.

13130302161793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 61236, while the sum is 40.

The spelling of 13130302161793 in words is "thirteen trillion, one hundred thirty billion, three hundred two million, one hundred sixty-one thousand, seven hundred ninety-three".