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131303100000000 = 28358437677
BaseRepresentation
bin11101110110101101100010…
…101000100010011100000000
3122012220110020210120001112210
4131312231202220202130000
5114202232222100000000
61143131451133222120
736441223136021055
oct3566554250423400
9565813223501483
10131303100000000
1138923371981295
1212887506631940
135835aa19a7646
14245d16534102c
15102a765717350
hex776b62a22700

131303100000000 has 324 divisors, whose sum is σ = 436822936502792. Its totient is φ = 35014080000000.

The previous prime is 131303099999957. The next prime is 131303100000029. The reversal of 131303100000000 is 1303131.

131303100000000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×1313031000000002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 299781162 + ... + 300218838.

Almost surely, 2131303100000000 is an apocalyptic number.

131303100000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131303100000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218411468251396).

131303100000000 is an abundant number, since it is smaller than the sum of its proper divisors (305519836502792).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131303100000000 is an frugal number, since it uses more digits than its factorization.

131303100000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437736 (or 437687 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 12.

Adding to 131303100000000 its reverse (1303131), we get a palindrome (131303101303131).

The spelling of 131303100000000 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred million", and thus it is an aban number.