Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …010110101101010001000011 |
3 | 122012220110021122022221201021 |
4 | 131312231203112231101003 |
5 | 114202232233144243404 |
6 | 1143131452244450311 |
7 | 36441223343626525 |
oct | 3566554326552103 |
9 | 565813248287637 |
10 | 131303112102979 |
11 | 38923378798453 |
12 | 1288750a6a9997 |
13 | 5835aa435447b |
14 | 245d166bb1a15 |
15 | 102a766808454 |
hex | 776b635ad443 |
131303112102979 has 2 divisors, whose sum is σ = 131303112102980. Its totient is φ = 131303112102978.
The previous prime is 131303112102961. The next prime is 131303112103021. The reversal of 131303112102979 is 979201211303131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131303112102979 - 25 = 131303112102947 is a prime.
It is not a weakly prime, because it can be changed into another prime (131303115102979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651556051489 + 65651556051490.
It is an arithmetic number, because the mean of its divisors is an integer number (65651556051490).
Almost surely, 2131303112102979 is an apocalyptic number.
131303112102979 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303112102979 is an equidigital number, since it uses as much as digits as its factorization.
131303112102979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 131303112102979 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twelve million, one hundred two thousand, nine hundred seventy-nine".
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