Base | Representation |
---|---|
bin | 11101110110101101100011… |
… | …111000101001011011000011 |
3 | 122012220110022021001222022102 |
4 | 131312231203320221123003 |
5 | 114202232242434001011 |
6 | 1143131453203301015 |
7 | 36441223512353663 |
oct | 3566554370513303 |
9 | 565813267058272 |
10 | 131303121000131 |
11 | 38923382814a73 |
12 | 1288751167a76b |
13 | 5835aa614b062 |
14 | 245d16804a1a3 |
15 | 102a7674b473b |
hex | 776b63e296c3 |
131303121000131 has 2 divisors, whose sum is σ = 131303121000132. Its totient is φ = 131303121000130.
The previous prime is 131303121000109. The next prime is 131303121000137. The reversal of 131303121000131 is 131000121303131.
It is a strong prime.
It is an emirp because it is prime and its reverse (131000121303131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131303121000131 - 214 = 131303120983747 is a prime.
It is a super-2 number, since 2×1313031210001312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131303121000137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651560500065 + 65651560500066.
It is an arithmetic number, because the mean of its divisors is an integer number (65651560500066).
Almost surely, 2131303121000131 is an apocalyptic number.
131303121000131 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303121000131 is an equidigital number, since it uses as much as digits as its factorization.
131303121000131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 131303121000131 its reverse (131000121303131), we get a palindrome (262303242303262).
The spelling of 131303121000131 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred twenty-one million, one hundred thirty-one", and thus it is an aban number.
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