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131303142134401 is a prime number
BaseRepresentation
bin11101110110101101100101…
…001001010001001010000001
3122012220110100201211201002011
4131312231211021101022001
5114202232313341300101
61143131455240252521
736441224160115636
oct3566554511211201
9565813321751064
10131303142134401
113892339373a506
1212887518771141
135835aaa63a843
14245d16ab8c18d
15102a76928b751
hex776b65251281

131303142134401 has 2 divisors, whose sum is σ = 131303142134402. Its totient is φ = 131303142134400.

The previous prime is 131303142134299. The next prime is 131303142134419. The reversal of 131303142134401 is 104431241303131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 87920158730625 + 43382983403776 = 9376575^2 + 6586576^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131303142134401 is a prime.

It is a super-2 number, since 2×1313031421344012 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (131303142134431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651571067200 + 65651571067201.

It is an arithmetic number, because the mean of its divisors is an integer number (65651571067201).

Almost surely, 2131303142134401 is an apocalyptic number.

It is an amenable number.

131303142134401 is a deficient number, since it is larger than the sum of its proper divisors (1).

131303142134401 is an equidigital number, since it uses as much as digits as its factorization.

131303142134401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 131303142134401 its reverse (104431241303131), we get a palindrome (235734383437532).

The spelling of 131303142134401 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred forty-two million, one hundred thirty-four thousand, four hundred one".