131303143441333 has 4 divisors (see below), whose sum is σ = 131303166634080. Its totient is φ = 131303120248588.

The previous prime is 131303143441291. The next prime is 131303143441361. The reversal of 131303143441333 is 333144341303131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131303143441333 - 2³⁷ = 131165704487861 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131303143441292 and 131303143441301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131303143448333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3126366 + ... + 16503952.

It is an arithmetic number, because the mean of its divisors is an integer number (32825791658520).

Almost surely, 2^{131303143441333} is an apocalyptic number.

It is an amenable number.

131303143441333 is a deficient number, since it is larger than the sum of its proper divisors (23192747).

131303143441333 is an equidigital number, since it uses as much as digits as its factorization.

131303143441333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23192746.

The product of its (nonzero) digits is 139968, while the sum is 37.

Adding to 131303143441333 its reverse (333144341303131), we get a palindrome (464447484744464).

The spelling of 131303143441333 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred forty-three million, four hundred forty-one thousand, three hundred thirty-three".