Base | Representation |
---|---|
bin | 11101110110101101100101… |
… | …001110010001111100001101 |
3 | 122012220110100211022110110022 |
4 | 131312231211032101330031 |
5 | 114202232314210321313 |
6 | 1143131455324351525 |
7 | 36441224204230433 |
oct | 3566554516217415 |
9 | 565813324273408 |
10 | 131303143448333 |
11 | 389233944576aa |
12 | 128875190a55a5 |
13 | 5835aaa9aa90c |
14 | 245d16b010d53 |
15 | 102a76944ac08 |
hex | 776b65391f0d |
131303143448333 has 2 divisors, whose sum is σ = 131303143448334. Its totient is φ = 131303143448332.
The previous prime is 131303143448317. The next prime is 131303143448353. The reversal of 131303143448333 is 333844341303131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125276913842089 + 6026229606244 = 11192717^2 + 2454838^2 .
It is a cyclic number.
It is not a de Polignac number, because 131303143448333 - 24 = 131303143448317 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131303143448353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65651571724166 + 65651571724167.
It is an arithmetic number, because the mean of its divisors is an integer number (65651571724167).
Almost surely, 2131303143448333 is an apocalyptic number.
It is an amenable number.
131303143448333 is a deficient number, since it is larger than the sum of its proper divisors (1).
131303143448333 is an equidigital number, since it uses as much as digits as its factorization.
131303143448333 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1119744, while the sum is 44.
The spelling of 131303143448333 in words is "one hundred thirty-one trillion, three hundred three billion, one hundred forty-three million, four hundred forty-eight thousand, three hundred thirty-three".
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