Base | Representation |
---|---|
bin | 10011000110110111011… |
… | …011010000001110001101 |
3 | 11122112012011221000202020 |
4 | 103012313123100032031 |
5 | 133003102323301031 |
6 | 2443111531320353 |
7 | 163602262151523 |
oct | 23066733201615 |
9 | 4575164830666 |
10 | 1313042400141 |
11 | 46694922748a |
12 | 1925872b00b9 |
13 | 96a861c3284 |
14 | 477a17d0313 |
15 | 2424de50096 |
hex | 131b76d038d |
1313042400141 has 4 divisors (see below), whose sum is σ = 1750723200192. Its totient is φ = 875361600092.
The previous prime is 1313042400037. The next prime is 1313042400143. The reversal of 1313042400141 is 1410042403131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1313042400141 - 27 = 1313042400013 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1313042400143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218840400021 + ... + 218840400026.
It is an arithmetic number, because the mean of its divisors is an integer number (437680800048).
Almost surely, 21313042400141 is an apocalyptic number.
It is an amenable number.
1313042400141 is a deficient number, since it is larger than the sum of its proper divisors (437680800051).
1313042400141 is an equidigital number, since it uses as much as digits as its factorization.
1313042400141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 437680800050.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1313042400141 its reverse (1410042403131), we get a palindrome (2723084803272).
The spelling of 1313042400141 in words is "one trillion, three hundred thirteen billion, forty-two million, four hundred thousand, one hundred forty-one".
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