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1313042400141 = 3437680800047
BaseRepresentation
bin10011000110110111011…
…011010000001110001101
311122112012011221000202020
4103012313123100032031
5133003102323301031
62443111531320353
7163602262151523
oct23066733201615
94575164830666
101313042400141
1146694922748a
121925872b00b9
1396a861c3284
14477a17d0313
152424de50096
hex131b76d038d

1313042400141 has 4 divisors (see below), whose sum is σ = 1750723200192. Its totient is φ = 875361600092.

The previous prime is 1313042400037. The next prime is 1313042400143. The reversal of 1313042400141 is 1410042403131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1313042400141 - 27 = 1313042400013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1313042400143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218840400021 + ... + 218840400026.

It is an arithmetic number, because the mean of its divisors is an integer number (437680800048).

Almost surely, 21313042400141 is an apocalyptic number.

It is an amenable number.

1313042400141 is a deficient number, since it is larger than the sum of its proper divisors (437680800051).

1313042400141 is an equidigital number, since it uses as much as digits as its factorization.

1313042400141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437680800050.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 1313042400141 its reverse (1410042403131), we get a palindrome (2723084803272).

The spelling of 1313042400141 in words is "one trillion, three hundred thirteen billion, forty-two million, four hundred thousand, one hundred forty-one".

Divisors: 1 3 437680800047 1313042400141