Base | Representation |
---|---|
bin | 1011111100010010101011… |
… | …0111001001100111010011 |
3 | 1201111020221112022120101222 |
4 | 2333010222313021213103 |
5 | 3210112112113433433 |
6 | 43532012124315255 |
7 | 2523433253354162 |
oct | 277045267114723 |
9 | 51436845276358 |
10 | 13130434124243 |
11 | 4202649831897 |
12 | 15809239a2b2b |
13 | 74326b78b7a7 |
14 | 3357330193d9 |
15 | 17b84569eb98 |
hex | bf12adc99d3 |
13130434124243 has 2 divisors, whose sum is σ = 13130434124244. Its totient is φ = 13130434124242.
The previous prime is 13130434124219. The next prime is 13130434124309. The reversal of 13130434124243 is 34242143403131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13130434124243 - 28 = 13130434123987 is a prime.
It is not a weakly prime, because it can be changed into another prime (13130434129243) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565217062121 + 6565217062122.
It is an arithmetic number, because the mean of its divisors is an integer number (6565217062122).
Almost surely, 213130434124243 is an apocalyptic number.
13130434124243 is a deficient number, since it is larger than the sum of its proper divisors (1).
13130434124243 is an equidigital number, since it uses as much as digits as its factorization.
13130434124243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 13130434124243 its reverse (34242143403131), we get a palindrome (47372577527374).
The spelling of 13130434124243 in words is "thirteen trillion, one hundred thirty billion, four hundred thirty-four million, one hundred twenty-four thousand, two hundred forty-three".
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