Base | Representation |
---|---|
bin | 1011111100010100110111… |
… | …1011001111101000000011 |
3 | 1201111022110112021002001002 |
4 | 2333011031323033220003 |
5 | 3210114313213300003 |
6 | 43532150341202215 |
7 | 2523453655542644 |
oct | 277051573175003 |
9 | 51438415232032 |
10 | 13131022400003 |
11 | 4202920902102 |
12 | 1580a68a0036b |
13 | 743333610a61 |
14 | 33578b1cd6cb |
15 | 17b87c153a88 |
hex | bf14decfa03 |
13131022400003 has 2 divisors, whose sum is σ = 13131022400004. Its totient is φ = 13131022400002.
The previous prime is 13131022399991. The next prime is 13131022400009. The reversal of 13131022400003 is 30000422013131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13131022400003 is a prime.
It is a super-2 number, since 2×131310224000032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13131022400009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565511200001 + 6565511200002.
It is an arithmetic number, because the mean of its divisors is an integer number (6565511200002).
Almost surely, 213131022400003 is an apocalyptic number.
13131022400003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131022400003 is an equidigital number, since it uses as much as digits as its factorization.
13131022400003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13131022400003 its reverse (30000422013131), we get a palindrome (43131444413134).
The spelling of 13131022400003 in words is "thirteen trillion, one hundred thirty-one billion, twenty-two million, four hundred thousand, three".
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