Base | Representation |
---|---|
bin | 111101001001010110… |
… | …0110001111010011001 |
3 | 110112221020100212221001 |
4 | 1322102230301322121 |
5 | 4122410404344233 |
6 | 140153441545001 |
7 | 12325663356241 |
oct | 1722254617231 |
9 | 415836325831 |
10 | 131310231193 |
11 | 50763225229 |
12 | 21547645161 |
13 | c4c848266b |
14 | 64d94d0b21 |
15 | 3637dc527d |
hex | 1e92b31e99 |
131310231193 has 2 divisors, whose sum is σ = 131310231194. Its totient is φ = 131310231192.
The previous prime is 131310231161. The next prime is 131310231307. The reversal of 131310231193 is 391132013131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130521070729 + 789160464 = 361277^2 + 28092^2 .
It is an emirp because it is prime and its reverse (391132013131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131310231193 - 25 = 131310231161 is a prime.
It is a super-2 number, since 2×1313102311932 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131310231133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65655115596 + 65655115597.
It is an arithmetic number, because the mean of its divisors is an integer number (65655115597).
Almost surely, 2131310231193 is an apocalyptic number.
It is an amenable number.
131310231193 is a deficient number, since it is larger than the sum of its proper divisors (1).
131310231193 is an equidigital number, since it uses as much as digits as its factorization.
131310231193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 28.
The spelling of 131310231193 in words is "one hundred thirty-one billion, three hundred ten million, two hundred thirty-one thousand, one hundred ninety-three".
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